(4x-5)(x^2-4x-1)=

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Solution for (4x-5)(x^2-4x-1)= equation:


Simplifying
(4x + -5)(x2 + -4x + -1) = 0

Reorder the terms:
(-5 + 4x)(x2 + -4x + -1) = 0

Reorder the terms:
(-5 + 4x)(-1 + -4x + x2) = 0

Multiply (-5 + 4x) * (-1 + -4x + x2)
(-5(-1 + -4x + x2) + 4x * (-1 + -4x + x2)) = 0
((-1 * -5 + -4x * -5 + x2 * -5) + 4x * (-1 + -4x + x2)) = 0
((5 + 20x + -5x2) + 4x * (-1 + -4x + x2)) = 0
(5 + 20x + -5x2 + (-1 * 4x + -4x * 4x + x2 * 4x)) = 0
(5 + 20x + -5x2 + (-4x + -16x2 + 4x3)) = 0

Reorder the terms:
(5 + 20x + -4x + -5x2 + -16x2 + 4x3) = 0

Combine like terms: 20x + -4x = 16x
(5 + 16x + -5x2 + -16x2 + 4x3) = 0

Combine like terms: -5x2 + -16x2 = -21x2
(5 + 16x + -21x2 + 4x3) = 0

Solving
5 + 16x + -21x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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